and — Expert Playground

Logical AND operator; returns True if both operands are true

Python Playground

import dis

def and_expr(a, b):
    return a and b

def and_chain(a, b, c):
    return a and b and c

print("a and b:")
dis.dis(and_expr)
print("\na and b and c:")
dis.dis(and_chain)

# 'and' compiles to:
# 1. Evaluate left operand
# 2. COPY + POP_JUMP_IF_FALSE -> skip right operand
# 3. POP (discard left value)
# 4. Evaluate right operand
# This is why 'and' returns values, not just True/False

Output

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'and' compiles to a conditional jump that skips the right operand if the left is falsy. The left value stays on the stack as the result, which is why 'and' returns the actual value, not a boolean.

Challenge

Try modifying the code above to explore different behaviors. Can you extend the example to handle a new use case?

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